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Joint and combined variations

So far we have seen one variable depending on one other. Many real-world relationships involve more than one input. Joint variation handles this: zz depends on xx and yy together, possibly with different kinds of proportion for each.

Concept

Joint variation. zz is jointly proportional to xx and yy (both directly) if

z=kxy.z = k x y.

Doubling xx doubles zz; doubling yy doubles zz. Doubling both quadruples zz.

Example: cost of paint is jointly proportional to wall area and number of coats. cost=kAc\text{cost} = k \cdot A \cdot c.

Combined variation. zz is directly proportional to xx and inversely proportional to yy:

z=kxy.z = k \dfrac{x}{y}.

Example: speed of work per worker. If WW workers finish JJ jobs in TT days, then WJ/TW \propto J/T (more jobs need more workers; more time needs fewer).

The work formula. Total work \propto (workers) ×\times (time). If the same job takes different worker-times, then for the same job, worker-time is constant.

Many-variable proportion. The general form:

z=kx1a1x2a2y1b1y2b2z = k \cdot \dfrac{x_1^{a_1} \cdot x_2^{a_2} \cdots}{y_1^{b_1} \cdot y_2^{b_2} \cdots}

For class VIII, you will mostly see two variables. Higher classes use more.

Setting up problems.

  1. Read carefully and identify which quantities are directly related to zz and which are inversely.
  2. Write the equation with kk.
  3. Use a known set of values to solve for kk.
  4. Plug in the new values.

Worked examples

Example 1. zz is jointly proportional to xx and yy. When x=4,y=5x = 4, y = 5, z=60z = 60. Find zz when x=6,y=8x = 6, y = 8.

  • 60=k45k=360 = k \cdot 4 \cdot 5 \Rightarrow k = 3.
  • z=368=144z = 3 \cdot 6 \cdot 8 = 144.

Example 2. zz varies directly with xx and inversely with yy. If z=12z = 12 when x=4,y=6x = 4, y = 6, find zz when x=7,y=14x = 7, y = 14.

  • z=kx/yz = k x / y. 12=k4/6k=1812 = k \cdot 4 / 6 \Rightarrow k = 18.
  • z=187/14=9z = 18 \cdot 7 / 14 = 9.

Example 3. If 1515 men can finish a job in 2020 days, how many days will it take 2525 men to finish the same job?

  • Worker-days are constant: 1520=25t15 \cdot 20 = 25 \cdot t. t=300/25=12t = 300/25 = 12 days.

Example 4. If 2020 workers can build 55 km of road in 3030 days, how many days for 3030 workers to build 99 km?

  • Worker-days per km: 2030/5=12020 \cdot 30 / 5 = 120 worker-days per km.
  • For 99 km: 1209=1080120 \cdot 9 = 1080 worker-days total.
  • For 3030 workers: 1080/30=361080 / 30 = 36 days.

Try it yourself

  1. zz is jointly proportional to xx and yy. When x=3,y=4x = 3, y = 4, z=60z = 60. Find zz when x=5,y=2x = 5, y = 2.
  2. zz varies directly with xx and inversely with yy. z=30z = 30 at x=6,y=4x = 6, y = 4. Find zz at x=4,y=6x = 4, y = 6.
  3. 2424 workers finish a job in 1818 days. How long for 3636 workers?
  4. If 88 workers can paint 44 houses in 66 days, how many days for 1212 workers to paint 99 houses?
  5. yxzy \propto \dfrac{x}{z} with y=10y = 10 when x=4,z=2x = 4, z = 2. Find yy at x=6,z=3x = 6, z = 3.
  6. The volume of a gas is inversely proportional to pressure (at fixed temperature). If V=2V = 2 L at P=3P = 3 atm, find VV at P=1.5P = 1.5 atm.
  7. The force needed to lift a weight is jointly proportional to the weight and the distance lifted. If 5050 N lifts 55 kg through 22 m, what is needed to lift 88 kg through 33 m?
  8. If 55 pumps fill a 10001000-L tank in 44 h, how many pumps for an 18001800-L tank in 33 h?

Activity / Insight

The gas-law experiment (Boyle's law). Take a syringe with no needle. Block the tip with your finger. Push the plunger gently , the volume of trapped air decreases and you feel resistance increasing. The relationship is PV=constantPV = \text{constant}, exactly the inverse proportion we have studied. This experiment, done by Robert Boyle in 16621662, started the modern science of gases.

Practice quiz

Quick check on this topic.

Quiz
Quick check : Joint and combined variation
5 questions · pick the best answer
Q1

z=kxyz = kxy with z=24z=24 at x=2,y=3x=2, y=3. Then k=k=

Q2

z=kx/yz = kx/y, z=12z=12 at x=4,y=2x=4,y=2. Find kk

Q3

1515 men can finish 55 km of road in 2020 days. 1010 men can finish same in

Q4

Force FF \propto mass ×\times acceleration. If F=20F = 20 at m=4,a=5m=4, a=5, find kk

Q5

Volume of gas 1/P\propto 1/P. V=2V=2 at P=3P=3. At P=6P=6, V=V=