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Chapter 7
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Special integrals and radical forms
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Quiz
Class XII
Quick check : Special integrals
6 questions
Question 1 of 6
Score:
0
/ 0
∫
d
x
x
2
+
16
=
\int \frac{dx}{x^2 + 16}=
∫
x
2
+
16
d
x
=
A
tan
−
1
(
x
/
4
)
+
C
\tan^{-1}(x/4) + C
tan
−
1
(
x
/4
)
+
C
B
1
4
tan
−
1
(
x
/
4
)
+
C
\frac{1}{4}\tan^{-1}(x/4) + C
4
1
tan
−
1
(
x
/4
)
+
C
C
1
16
tan
−
1
x
+
C
\frac{1}{16}\tan^{-1} x + C
16
1
tan
−
1
x
+
C
D
ln
(
x
2
+
16
)
+
C
\ln(x^2 + 16) + C
ln
(
x
2
+
16
)
+
C
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