Math Lab

Factor Theorem Checker

Polynomials · Class IX

Pick a candidate k. Is (x - k) a factor of p(x) = x^3 + bx^2 + cx + d?

1
type a value
-55
-6
type a value
-55
11
type a value
-1010
-6
type a value
-1010
Live values
  • p(k)0
  • Is (x - k) a factor?1
xy
  • y = p(x)

Formulas in this lab

  • p(k)
    p(k)=k3+bk2+ck+dp(k) = k^3 + bk^2 + ck + d
  • Is (x - k) a factor?
    p(k)=0?p(k) = 0?
Tip: Try k = 1, 2, 3 with the default p(x) = x^3 - 6x^2 + 11x - 6 , each gives p(k) = 0.

Frequently asked questions

What does the factor theorem say?

The factor theorem states that $(x - k)$ is a factor of $p(x)$ if and only if $p(k) = 0$. So to check whether $(x - 2)$ divides $p(x) = x^3 - 8$, just compute $p(2) = 0$, which confirms it is a factor.

How do I use this lab?

Choose b, c, d to fix the cubic and slide candidate k. The lab evaluates $p(k)$; a green tick appears when $p(k) = 0$. Try $p(x) = x^3 - 4x^2 + x + 6$ and test k = -1, 2, 3 to find all factors.

Common mistake on this topic

Students plug in $k$ with the wrong sign. Remember: for the factor $(x - k)$, substitute $+k$, not $-k$. So $(x + 3)$ corresponds to $k = -3$, and you check $p(-3)$.

Where is the factor theorem useful?

Factor theorem makes solving higher-degree equations much easier and is the basis for splitting middle terms. In real life it helps reverse-engineer recipes: if you know one ingredient ratio is a factor, the whole formula simplifies.