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Sequences and notation

When we list numbers in a specific order, we are forming a sequence. The list 2,4,6,8,10,2, 4, 6, 8, 10, \dots is a sequence of even numbers; so is 1,1,2,3,5,8,13,1, 1, 2, 3, 5, 8, 13, \dots (the Fibonacci sequence). What distinguishes a sequence from a set is order: the third entry is the third entry, and you cannot swap it with the fifth without changing the sequence.

Definitions

A sequence is a function whose domain is the set of natural numbers (or some initial segment {1,2,,n}\{1, 2, \dots, n\}). Instead of writing f(1),f(2),f(3),f(1), f(2), f(3), \dots we write a1,a2,a3,a_1, a_2, a_3, \dots The number ana_n is the nn-th term or general term.

A finite sequence has finitely many terms: a1,a2,,ana_1, a_2, \dots, a_n. An infinite sequence continues indefinitely: a1,a2,a3,a_1, a_2, a_3, \dots

Three ways to specify a sequence:

  1. By formula: an=2n+1a_n = 2n + 1 gives 3,5,7,9,3, 5, 7, 9, \dots
  2. By recursion (each term depends on previous ones): a1=1a_1 = 1, an=an1+2a_n = a_{n-1} + 2.
  3. By rule in words: "the nn-th prime number".

A series is the sum of the terms of a sequence: a1+a2+a3+a_1 + a_2 + a_3 + \dots When the sequence is finite, the series is a finite sum. When it is infinite, the series may or may not have a meaningful value , convergence is a Class XII topic.

Sigma notation

The Greek letter Σ\Sigma ("sigma") condenses sums: k=1nak=a1+a2++an.\sum_{k=1}^{n} a_k = a_1 + a_2 + \dots + a_n.

The variable kk (the index) takes every integer from 11 to nn. The label below Σ\Sigma is the starting index; the label above is the ending index. Index names are interchangeable: k=1nak=j=1naj\sum_{k=1}^n a_k = \sum_{j=1}^n a_j.

Some standard sums you should commit to memory immediately: k=1n1=n,k=1nk=n(n+1)2,k=1nk2=n(n+1)(2n+1)6,k=1nk3=(n(n+1)2)2.\sum_{k=1}^n 1 = n, \quad \sum_{k=1}^n k = \frac{n(n+1)}{2}, \quad \sum_{k=1}^n k^2 = \frac{n(n+1)(2n+1)}{6}, \quad \sum_{k=1}^n k^3 = \left(\frac{n(n+1)}{2}\right)^2.

Properties of Σ\Sigma

Sigma is linear: (cak)=cak,(ak+bk)=ak+bk.\sum (c\, a_k) = c \sum a_k, \quad \sum (a_k + b_k) = \sum a_k + \sum b_k.

But not multiplicative: (akbk)(ak)(bk)\sum (a_k b_k) \ne (\sum a_k)(\sum b_k) in general.

Worked examples

Example 1. Write the first five terms of an=3n2a_n = 3n - 2.

a1=1,a2=4,a3=7,a4=10,a5=13a_1 = 1, a_2 = 4, a_3 = 7, a_4 = 10, a_5 = 13.

Example 2. Find the nn-th term of 1,4,9,16,25,1, 4, 9, 16, 25, \dots

These are 12,22,32,1^2, 2^2, 3^2, \dots so an=n2a_n = n^2.

Example 3. A sequence is defined by a1=2a_1 = 2, an+1=2an+1a_{n+1} = 2 a_n + 1. Find a4a_4.

a1=2a_1 = 2, a2=5a_2 = 5, a3=11a_3 = 11, a4=23a_4 = 23.

Example 4. Compute k=120(2k1)\sum_{k=1}^{20} (2k - 1).

k=120(2k1)=2k=120kk=1201=22021220=42020=400\sum_{k=1}^{20} (2k - 1) = 2 \sum_{k=1}^{20} k - \sum_{k=1}^{20} 1 = 2 \cdot \dfrac{20 \cdot 21}{2} - 20 = 420 - 20 = 400.

(This is the sum of the first 2020 odd numbers, which equals 202=40020^2 = 400.)

Example 5. Compute k=110k(k+1)\sum_{k=1}^{10} k(k + 1).

k(k+1)=k2+k=1011216+10112=385+55=440\sum k(k+1) = \sum k^2 + \sum k = \dfrac{10 \cdot 11 \cdot 21}{6} + \dfrac{10 \cdot 11}{2} = 385 + 55 = 440.

Try it yourself

  1. Find the first five terms of an=n2na_n = n^2 - n.
  2. Write the nn-th term of 2,5,10,17,26,2, 5, 10, 17, 26, \dots
  3. A sequence: a1=1,a2=1,an=an1+an2a_1 = 1, a_2 = 1, a_n = a_{n-1} + a_{n-2}. Find a7a_7.
  4. Compute k=115(3k+2)\sum_{k=1}^{15} (3k + 2).
  5. Compute k=112k2\sum_{k=1}^{12} k^2.
  6. Write in sigma notation: 1+4+7+10++311 + 4 + 7 + 10 + \dots + 31.
  7. Write the nn-th term of 12,23,34,45,\dfrac{1}{2}, \dfrac{2}{3}, \dfrac{3}{4}, \dfrac{4}{5}, \dots
  8. Find k=1n(k2k)\sum_{k=1}^{n} (k^2 - k).
  9. A sequence has an=nn+1a_n = \dfrac{n}{n + 1}. Find a99a_{99}.
  10. Compute k=120(k2+2k)\sum_{k=1}^{20} (k^2 + 2k).
  11. Determine if 7,10,13,16,7, 10, 13, 16, \dots has a100=304a_{100} = 304. Verify.
  12. Write the recursion that produces 3,9,27,81,3, 9, 27, 81, \dots

Pitfalls / Tricks

  • "Sequence" and "series" are distinct: the first is a list, the second is a sum.
  • A recursive definition needs initial values plus a recurrence.
  • (akbk)(ak)(bk)\sum (a_k b_k) \ne (\sum a_k)(\sum b_k) , never distribute multiplication over sigma like that.
  • Insight. When you see an unfamiliar series, first ask which formula gives the general term? Once you have aka_k, summation becomes algebra.

Practice quiz

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Quick check : Sequences and notation
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