Math Lab
Home/Class XI/Chapter 7

Chapter 7: Binomial Theorem

How would you expand (1+x)20(1 + x)^{20} without multiplying twenty copies by hand? The binomial theorem answers this in a single line, giving every term and every coefficient by formula.

For positive integer exponents the formula is (a+b)n=r=0n(nr)anrbr.(a + b)^n = \sum_{r = 0}^{n} \binom{n}{r}\,a^{n - r}\,b^r. Each coefficient (nr)\binom{n}{r} counts the number of ways to choose which rr of the nn factors contribute the bb , the same combinations you learned in Chapter 6.

The proof connects two threads of the course: algebra (multiplying nn copies) and combinatorics (counting choices). Every later use of binomial coefficients , in probability, in series, in derivatives of polynomials , descends from this single identity.

In Class XII you will extend the theorem to any real exponent (using calculus). For now we focus on integer exponents and master:

  • writing the expansion;
  • finding any specific term (the general term);
  • identifying the middle term(s);
  • using the expansion to compute values and prove identities;
  • properties of binomial coefficients like (nr)=(nnr)\binom{n}{r} = \binom{n}{n - r} and r(nr)=2n\sum_r \binom{n}{r} = 2^n.

What's inside

  1. Binomial theorem for positive integral indices , statement and proof.
  2. General term and any specific term , find Tr+1T_{r+1}.
  3. Middle term(s) and term independent of xx.
  4. Properties and identities of binomial coefficients.
  5. Applications , divisibility, numerical estimates, identities.
  6. Multinomial preview and miscellaneous problems.

Key results / Formula card

ConceptFormula
Expansion(a+b)n=r=0n(nr)anrbr(a + b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r
General term (Tr+1T_{r+1})Tr+1=(nr)anrbrT_{r+1} = \binom{n}{r} a^{n-r} b^r
Middle term, nn evenTn/2+1=(nn/2)an/2bn/2T_{n/2 + 1} = \binom{n}{n/2} a^{n/2} b^{n/2}
Middle terms, nn oddT(n+1)/2T_{(n+1)/2} and T(n+3)/2T_{(n+3)/2}
Sum of coefficientsr=0n(nr)=2n\sum_{r=0}^{n} \binom{n}{r} = 2^n
Alternating sumr=0n(1)r(nr)=0\sum_{r=0}^{n} (-1)^r \binom{n}{r} = 0
Symmetry(nr)=(nnr)\binom{n}{r} = \binom{n}{n - r}
Pascal(nr)=(n1r1)+(n1r)\binom{n}{r} = \binom{n-1}{r-1} + \binom{n-1}{r}
r(nr)=n(n1r1)r \binom{n}{r} = n \binom{n-1}{r-1}

How to read this chapter

For any problem, the first step is to identify nn, aa, bb. The second is to write Tr+1T_{r+1} and pick the right rr. Keep Pascal's triangle in your notebook for the first few nn and you can verify any expansion at a glance.

Sub-topics

6 pages

Practice quiz

Answer the questions; explanations appear after each.

Quiz
Chapter 7 : Binomial Theorem: Mixed practice
10 questions · pick the best answer
Q1

Q2

Q3

Q4

Q5

Q6

Q7

Q8

Q9

Q10