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Modulus and conjugate

Two of the most important operations on complex numbers are the modulus (size) and the conjugate (reflection in the real axis). They satisfy a dozen clean identities, and together they let us divide complex numbers and prove inequalities.

Definitions

Let z=a+biz = a + bi with a,bRa, b \in \mathbb{R}.

The modulus (or absolute value) of zz is z=a2+b2.|z| = \sqrt{a^2 + b^2}. It is the distance of zz from the origin in the Argand plane. For real zz, this agrees with the ordinary x|x| , so the notation is unambiguous.

The conjugate of zz is zˉ=abi.\bar{z} = a - bi. It is the reflection of zz across the real axis.

The master identity

zzˉ=(a+bi)(abi)=a2b2i2=a2+b2=z2.\boxed{z\,\bar{z} = (a + bi)(a - bi) = a^2 - b^2 i^2 = a^2 + b^2 = |z|^2.}

This single identity is the engine behind division of complex numbers, and behind the inequality theory.

Properties of conjugate

For all z,wCz, w \in \mathbb{C}:

  1. (zˉ)=z\overline{(\bar{z})} = z (involution).
  2. z+w=zˉ+wˉ\overline{z + w} = \bar{z} + \bar{w}.
  3. zw=zˉwˉ\overline{zw} = \bar{z}\,\bar{w}.
  4. z/w=zˉ/wˉ\overline{z/w} = \bar{z}/\bar{w} (when w0w \ne 0).
  5. z+zˉ=2Re(z)z + \bar{z} = 2\,\text{Re}(z).
  6. zzˉ=2iIm(z)z - \bar{z} = 2i\,\text{Im}(z).
  7. z=zˉ    zz = \bar{z} \iff z is real. z=zˉ    zz = -\bar{z} \iff z is purely imaginary.

Each is proved by direct expansion.

Properties of modulus

For all z,wCz, w \in \mathbb{C}:

  1. z0|z| \ge 0, with equality iff z=0z = 0.
  2. z=zˉ|z| = |\bar{z}|.
  3. zw=zw|zw| = |z| \cdot |w| (multiplicative).
  4. zw=zw\left|\dfrac{z}{w}\right| = \dfrac{|z|}{|w|}.
  5. zn=zn|z^n| = |z|^n.
  6. Triangle inequality: z+wz+w|z + w| \le |z| + |w|.
  7. Reverse triangle: zwzw\big||z| - |w|\big| \le |z - w|.

The multiplicative property is striking: complex multiplication multiplies sizes. The triangle inequality is a direct generalisation of the inequality x+yx+y|x + y| \le |x| + |y| for real numbers.

Proof of zw=zw|zw| = |z||w|

zw2=(zw)(zw)=(zw)(zˉwˉ)=(zzˉ)(wwˉ)=z2w2|zw|^2 = (zw)(\overline{zw}) = (zw)(\bar{z}\bar{w}) = (z\bar{z})(w\bar{w}) = |z|^2 |w|^2.

Taking positive square roots, zw=zw|zw| = |z||w|. \qed\qed

Computing 1/z1/z

For z0z \ne 0: 1z=zˉzzˉ=zˉz2=abia2+b2.\frac{1}{z} = \frac{\bar{z}}{z \bar{z}} = \frac{\bar{z}}{|z|^2} = \frac{a - bi}{a^2 + b^2}.

This is the practical method for dividing complex numbers.

Worked examples

Example 1. Find the modulus and conjugate of z=34iz = 3 - 4i.

z=9+16=5|z| = \sqrt{9 + 16} = 5. zˉ=3+4i\bar{z} = 3 + 4i.

Example 2. Verify zw=zw|zw| = |z||w| for z=1+iz = 1 + i, w=2iw = 2 - i.

zw=2i+2ii2=3+izw = 2 - i + 2i - i^2 = 3 + i. zw=9+1=10|zw| = \sqrt{9 + 1} = \sqrt{10}. z=2,w=5|z| = \sqrt{2}, |w| = \sqrt{5}, product 10\sqrt{10}. Verified.

Example 3. Find 3+2i1i\dfrac{3 + 2i}{1 - i} using the conjugate technique.

(3+2i)(1+i)(1i)(1+i)=3+3i+2i+2i21+1=1+5i2=12+52i\dfrac{(3 + 2i)(1 + i)}{(1 - i)(1 + i)} = \dfrac{3 + 3i + 2i + 2i^2}{1 + 1} = \dfrac{1 + 5i}{2} = \dfrac{1}{2} + \dfrac{5}{2} i.

Example 4. Find all zz with z+zˉ=4z + \bar{z} = 4 and zzˉ=13z \bar{z} = 13.

z+zˉ=2Re(z)=4Re(z)=2z + \bar{z} = 2\text{Re}(z) = 4 \Rightarrow \text{Re}(z) = 2. zzˉ=z2=13z \bar{z} = |z|^2 = 13. If z=2+biz = 2 + bi, then z2=4+b2=13b=±3|z|^2 = 4 + b^2 = 13 \Rightarrow b = \pm 3. So z=2+3iz = 2 + 3i or z=23iz = 2 - 3i.

Example 5 (harder). Show that if z=1|z| = 1, then z+1zz + \dfrac{1}{z} is real.

If z=1|z| = 1, then zzˉ=1z\bar{z} = 1, so zˉ=1/z\bar{z} = 1/z. Hence 1z=zˉ\dfrac{1}{z} = \bar{z}, and z+1z=z+zˉ=2Re(z)Rz + \dfrac{1}{z} = z + \bar{z} = 2\text{Re}(z) \in \mathbb{R}. \qed\qed

Try it yourself

  1. Find z|z| and zˉ\bar{z} for z=1+2iz = -1 + 2i.
  2. Show 3+4i=5|3 + 4i| = 5, 512i=13|5 - 12i| = 13.
  3. Find zz such that zzˉ=25z \bar{z} = 25 and z+zˉ=6z + \bar{z} = 6.
  4. Verify the triangle inequality for z=3+4i,w=512iz = 3 + 4i, w = 5 - 12i.
  5. Show (z+w)=zˉ+wˉ\overline{(z + w)} = \bar{z} + \bar{w} by direct computation.
  6. If z=2+iz = 2 + i, compute 1z\dfrac{1}{z}.
  7. Find all zz with z1=1|z - 1| = 1 and zzˉ=1z \bar{z} = 1.
  8. Prove z2+w2=12(z+w2+zw2)|z|^2 + |w|^2 = \tfrac{1}{2}(|z + w|^2 + |z - w|^2) (parallelogram law).
  9. If z+1=z1|z + 1| = |z - 1|, prove zz is purely imaginary.
  10. Find all zz with z=zˉ2z = \bar{z}^2.
  11. Show z+w2=z2+w2+2Re(zwˉ)|z + w|^2 = |z|^2 + |w|^2 + 2\text{Re}(z \bar{w}).
  12. If z1=z2=z3=1|z_1| = |z_2| = |z_3| = 1 and z1+z2+z3=0z_1 + z_2 + z_3 = 0, prove z1+z2=1|z_1 + z_2| = 1.

Pitfalls / Tricks

  • z|z| is a real number, never complex. So z0|z| \ge 0 and z2z2|z|^2 \ne z^2.
  • z2=zˉ2\overline{z^2} = \bar{z}^2, but z2z2z^2 \ne |z|^2 unless zz is real.
  • The triangle inequality is not always tight: equality holds iff z,wz, w lie on the same ray from the origin.
  • Insight. zzˉ=z2z\bar{z} = |z|^2 is the key identity. Whenever you see zz in a denominator or under a modulus squared, multiply by its conjugate.

Practice quiz

Quick check on this topic.

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Quick check : Modulus and conjugate
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