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Calendar magic

A calendar looks like a plain grid, but the rule "go right by 11, go down by 77" hides quite a bit of algebra. With it you can build "magic" tricks: ask a friend to circle a 2×22 \times 2 block of dates and tell you only their sum. You can recover all four dates. Or you can grab a 3×33 \times 3 block , the central date is always one-ninth of the total. Algebra explains everything.

Concept

The calendar rule. If aa is any date in a month, then the date one column to the right is a+1a + 1 (the next day) and the date one row below is a+7a + 7 (the same weekday a week later). So a 2×22 \times 2 block on a calendar looks like this:

aa+1a+7a+8\begin{array}{|c|c|} \hline a & a+1 \\ \hline a + 7 & a + 8 \\ \hline \end{array}

Sum of a 2×22 \times 2 block. Add the four numbers:

a+(a+1)+(a+7)+(a+8)=4a+16.a + (a+1) + (a+7) + (a+8) = 4a + 16.

So if the sum is SS, then a=S164a = \dfrac{S - 16}{4}. From aa you read off the other three.

Example. Friend says "sum is 3636". Then 4a+16=364a=20a=54a + 16 = 36 \Rightarrow 4a = 20 \Rightarrow a = 5. The block is {5,6,12,13}\{5, 6, 12, 13\}.

3×33 \times 3 block magic. Let the centre date be cc. The block is:

c8c7c6c1cc+1c+6c+7c+8\begin{array}{|c|c|c|} \hline c-8 & c-7 & c-6 \\ \hline c-1 & c & c+1 \\ \hline c+6 & c+7 & c+8 \\ \hline \end{array}

(Each row differs by 77 from the next; each column differs by 11 from the next.) Summing all nine:

9c.9c.

The minus and plus terms cancel out. So the sum of any 3×33 \times 3 calendar block is exactly 99 times its centre. Friend says "sum is 171171"; then the centre is 171/9=19171/9 = 19, and you can name all nine dates.

Some other slick patterns.

  • A horizontal 1×41 \times 4 block (say a,a+1,a+2,a+3a, a+1, a+2, a+3) sums to 4a+64a + 6.
  • A vertical 4×14 \times 1 block (a,a+7,a+14,a+21a, a+7, a+14, a+21) sums to 4a+424a + 42.
  • A "diagonal" pair {a,a+8}\{a, a+8\} and {a+1,a+7}\{a+1, a+7\} both sum to 2a+82a + 8 , a knight's-move identity.

These tricks work in any month on any calendar, because the relative arrangement of dates in a grid is fixed. You just need to be careful near the edges of the month, where the pattern can be cut short.

Worked examples

Example 1. 2×22 \times 2 block from a calendar sums to 4040. Find the four dates.

  • 4a+16=40a=64a + 16 = 40 \Rightarrow a = 6. Block: 6,7,13,146, 7, 13, 14.

Example 2. 2×22 \times 2 block sums to 8080. Find the dates.

  • 4a+16=80a=164a + 16 = 80 \Rightarrow a = 16. Block: 16,17,23,2416, 17, 23, 24.

Example 3. 3×33 \times 3 block on a calendar has sum 108108. Find the centre and the dates.

  • Centre =108/9=12= 108/9 = 12. The block has 4,5,6,11,12,13,18,19,204, 5, 6, 11, 12, 13, 18, 19, 20.

Example 4. A friend picks a row of three consecutive dates (e.g. 9,10,119, 10, 11). Their sum is SS. Find a formula for the middle date.

  • Sum =3(middle)= 3 \cdot (\text{middle}), so middle =S/3= S/3. Quick and elegant.

Try it yourself

  1. A 2×22 \times 2 block on a calendar sums to 5252. Find the dates.
  2. A 2×22 \times 2 block sums to 9696. Find the dates.
  3. A 3×33 \times 3 block sums to 9090. Find the centre.
  4. A horizontal block of 55 consecutive dates has middle 2020. Find the sum.
  5. In a 2×22 \times 2 block, the bottom-right is 1919. Find the sum of the block.
  6. A 4×14 \times 1 vertical column has sum 7070. Find the top date.
  7. Why does a 3×33 \times 3 calendar block always sum to 99 times its centre?
  8. Invent a 2×32 \times 3 block calendar trick. What is its sum in terms of the top-left aa?

Activity

Calendar guess. Open your favourite month. Cover the calendar with your hand and ask a friend to draw a 2×22 \times 2 box of dates and tell you only the sum. Use the formula a=(S16)/4a = (S - 16)/4 to find the top-left and announce all four dates correctly. Try it three times. Then explain why it always works , using algebra.

Practice quiz

Quick check on this topic.

Quiz
Quick check : Calendar magic
5 questions · pick the best answer
Q1

2×22 \times 2 block sum formula in terms of top-left aa

Q2

2×22 \times 2 sum is 8080. Top-left

Q3

3×33 \times 3 block with centre cc: sum is

Q4

3×33 \times 3 block sum is 108108. Centre

Q5

Three consecutive horizontal dates sum to SS. Middle date