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Chapter 1: A Square and A Cube

Stack one row of 55 tiles. Add another row of 55. Keep going until you have 55 rows. You have built a 5×55 \times 5 square holding 2525 tiles. Now imagine stacking five copies of that square on top of each other , you would get a perfect cube of 125125 tiles. The numbers 2525 and 125125 are not random; they belong to two of the most useful families in mathematics: squares and cubes.

Why care about these? Almost every formula in geometry, physics, and engineering hides a square or a cube somewhere. The area of a piece of land is measured in square metres. The volume of a water tank is measured in cubic metres. Doubling the side of a photograph makes its area 44 times bigger, not 22. Doubling the side of an ice cube makes it 88 times heavier. Squares and cubes are the secret reasons.

In this chapter you will learn how to recognise a perfect square or perfect cube on sight, find its square root or cube root, and use prime factorisation as a powerful microscope to see inside any number. You will also meet several patterns , like the sum of the first nn odd numbers being a square , that have entertained mathematicians for thousands of years, from ancient India to modern computer science.

By the end you will be comfortable with the symbols \sqrt{\,} and 3\sqrt[3]{\,}, you will know which numbers can never be perfect squares, and you will see why 1,8,27,64,1, 8, 27, 64, \dots keep showing up in surprising places.

What's inside

  1. Square numbers and their patterns , what a perfect square is, and the patterns hidden inside the list 1,4,9,16,1, 4, 9, 16, \dots
  2. Square roots and how to find them , undoing a square, using prime factorisation and estimation.
  3. Cube numbers and their patterns , perfect cubes, properties, and a famous taxi-cab story.
  4. Cube roots , undoing a cube using prime factorisation.
  5. Squares, cubes and the real world , area, volume, growth, and a few puzzles.

Key results

IdeaSymbol / formulaExample
Square of nnn2=n×nn^2 = n \times n72=497^2 = 49
Cube of nnn3=n×n×nn^3 = n \times n \times n43=644^3 = 64
Square rootn2=n\sqrt{n^2} = n (for n0n \ge 0)81=9\sqrt{81} = 9
Cube rootn33=n\sqrt[3]{n^3} = n1253=5\sqrt[3]{125} = 5
Sum of first nn odd numbers1+3+5++(2n1)=n21 + 3 + 5 + \dots + (2n-1) = n^21+3+5+7=16=421 + 3 + 5 + 7 = 16 = 4^2
Square of (n+1)(n+1)(n+1)2=n2+(2n+1)(n+1)^2 = n^2 + (2n+1)112=100+21=12111^2 = 100 + 21 = 121
Difference of consecutive cubes(n+1)3n3=3n2+3n+1(n+1)^3 - n^3 = 3n^2 + 3n + 15343=75+15+1=915^3 - 4^3 = 75 + 15 + 1 = 91

Last-digit rule. A perfect square can only end in 0,1,4,5,6,90, 1, 4, 5, 6, 9. So 10271027 can never be a square , it ends in 77. A perfect cube, however, can end in any digit.

How to read this chapter

Keep grid paper and a small box of cubes nearby. Squares and cubes are visual ideas; almost every result becomes obvious once you draw it. After each worked example, hide the answer and try it from scratch.

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