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Evaluating expressions

Once you have an algebraic expression and the value of each letter, you simply substitute and apply BODMAS to compute the numeric result.

Idea

To evaluate 3x+53x + 5 at x=4x = 4:

  1. Replace xx by 44: 3(4)+53(4) + 5.
  2. Use BODMAS: multiplication first 3×4=123 \times 4 = 12, then addition 12+5=1712 + 5 = 17.

So 3x+5=173x + 5 = 17 when x=4x = 4.

A few cautions:

  • When you substitute a negative number, use brackets: 3(2)+5=6+5=13(-2) + 5 = -6 + 5 = -1. Without brackets you may forget the sign.
  • For an expression with several letters like 2x+3y2x + 3y, you need a value for each letter.
  • For squared or cubed letters: x2x^2 at x=5x = 5 is 52=255^2 = 25, not 5×25 \times 2.

Substitution lets us see how a single expression takes on many values as the variable changes. The expression 2x+32x + 3 at x=0,1,2,3x = 0, 1, 2, 3 gives 3,5,7,93, 5, 7, 9. The pattern (each value is 22 more than the last) is the rate of change, and the constant 33 is the value at x=0x = 0.

This idea , plug in a value, get a result , is the foundation of formulas, functions, and graphs in higher classes.

Worked examples

Example 1. Evaluate 4y34y - 3 at y=5y = 5.

4(5)3=203=174(5) - 3 = 20 - 3 = 17.

Example 2. Evaluate 2x+3y2x + 3y at x=4x = 4, y=1y = 1.

2(4)+3(1)=8+3=112(4) + 3(1) = 8 + 3 = 11.

Example 3. Evaluate x2+2xx^2 + 2x at x=3x = -3.

x2=(3)2=9x^2 = (-3)^2 = 9 and 2x=2(3)=62x = 2(-3) = -6. Sum: 9+(6)=39 + (-6) = 3.

Example 4. A taxi charges 12x+5012x + 50 rupees for xx km. Find the fare for (i) 55 km, (ii) 2020 km.

(i) 12(5)+50=60+50=\rupee11012(5) + 50 = 60 + 50 = \rupee 110. (ii) 12(20)+50=240+50=\rupee29012(20) + 50 = 240 + 50 = \rupee 290.

Try it yourself

  1. Evaluate 5n25n - 2 at n=3n = 3.
  2. Evaluate a+ba + b at a=7a = 7, b=2b = -2.
  3. Evaluate 2x22x^2 at x=4x = 4.
  4. Evaluate 3(x+5)3(x + 5) at x=2x = 2.
  5. The perimeter of a square is 4s4s. Find it when s=9s = 9 cm.
  6. Evaluate 5x3y5x - 3y at x=4x = 4, y=2y = 2.
  7. Evaluate x+y2\tfrac{x + y}{2} at x=6x = 6, y=10y = 10.
  8. The cost expression is C=20n+100C = 20n + 100. Find CC for n=0,5,10n = 0, 5, 10.

Activity

Make a table for y=2x+1y = 2x + 1 at x=0,1,2,3,4,5x = 0, 1, 2, 3, 4, 5. Plot (x,y)(x, y) on graph paper. Notice they form a straight line , that's a sneak peek of next year's algebra.

Practice quiz

Quick check on this topic.

Quiz
Quick check : Evaluating expressions
5 questions · pick the best answer
Q1

5n25n-2 at n=3n=3 is:

Q2

a+ba+b at a=7,b=2a=7, b=-2 is:

Q3

2x22x^2 at x=4x=4 is:

Q4

3(x+5)3(x+5) at x=2x=2 is:

Q5

x+y2\tfrac{x+y}{2} at x=6,y=10x=6, y=10 is: