Math Lab
Home/Class VI/Ch 6/Areas of irregular shapes

Areas of irregular shapes

Real-life shapes are rarely tidy rectangles or triangles. Houses have odd-shaped rooms; states on a map have curvy borders; ponds and gardens have irregular outlines. To find the area of these irregular shapes, we use a few clever strategies.

Concept

Strategy 1: Split into known shapes

If a shape is made of straight edges, you can almost always split it into rectangles and triangles. Find the area of each piece, then add them up.

For example, an L-shaped room can be split into two rectangles. A T-shaped path can be split into three rectangles. The trick is to look for natural lines that cut the shape into the simplest possible pieces.

Strategy 2: Subtract from a bigger shape

Sometimes it is easier to surround the shape with a big rectangle, find the area of the big rectangle, and subtract the pieces that aren't part of the shape. This works especially well for shapes with "notches" cut out of them.

For example, a rectangle with a square hole in the middle: find the rectangle area, subtract the square area.

Strategy 3: Count unit squares (for curved or irregular figures)

For shapes whose boundary is curved (like a leaf, a country, or a pond), exact formulas are not available. Place the shape on graph paper and:

  • Count the fully inside squares as 11 each.
  • Count the partly inside squares (any cell whose more than half is inside the shape) as 11, those with less than half as 00. Alternatively count all partial squares as 12\frac{1}{2} each.
  • Ignore squares barely touching the boundary.

This gives an estimate, not an exact answer , but it works for any shape, and gets more accurate as you use finer grid paper.

Pick's theorem (peek ahead)

There is a beautiful exact formula for the area of a polygon whose corners sit on grid points (called a lattice polygon):

Area=i+b21\text{Area} = i + \frac{b}{2} - 1

where ii is the number of grid points strictly inside the polygon, and bb is the number of grid points on its boundary. This is Pick's theorem. You will see it again in higher classes, but it is fun to test it on small examples now.

Worked examples

Example 1. An L-shaped room is made of a 55 m by 44 m rectangle and a 33 m by 22 m rectangle joined along one 22-m edge. Find its area.

  • Piece 11: 5×4=205 \times 4 = 20 m².
  • Piece 22: 3×2=63 \times 2 = 6 m².
  • Total area =20+6=26= 20 + 6 = 26 m².

Example 2. A rectangle is 1212 m by 99 m. A square swimming pool of side 33 m is dug out of the middle. Find the remaining area.

  • Rectangle area =12×9=108= 12 \times 9 = 108 m².
  • Pool area =32=9= 3^2 = 9 m².
  • Remaining =1089=99= 108 - 9 = 99 m².

Example 3. A path of width 11 m is built around the inside of a rectangular plot of 1010 m by 88 m. Find the area of the path.

  • Outer rectangle: 10×8=8010 \times 8 = 80 m².
  • Inner rectangle (inside the path): (102)×(82)=8×6=48(10 - 2) \times (8 - 2) = 8 \times 6 = 48 m².
  • Path area =8048=32= 80 - 48 = 32 m².

Example 4. A leaf is placed on 11-cm graph paper. Counting: 1414 full squares inside, and 1818 partial squares. Estimate its area.

  • Estimate =14×1+18×12=14+9=23= 14 \times 1 + 18 \times \frac{1}{2} = 14 + 9 = 23 cm².

Example 5. Use Pick's theorem to verify the area of a triangle with vertices at (0,0)(0,0), (4,0)(4,0), (0,3)(0,3).

  • Boundary lattice points: on (0,0)(0,0)-(4,0)(4,0) we have 55 points (including ends). On (4,0)(4,0)-(0,3)(0,3) , the gcd of 44 and 33 is 11, so 1+1=21+1 = 2 end points. On (0,3)(0,3)-(0,0)(0,0) we have 44 points. Avoid double-counting corners: b=5+2+43=8b = 5 + 2 + 4 - 3 = 8. Hmm , careful: gcd of distances determines interior points on each segment. Let me redo: segment (0,0)(0,0) to (4,0)(4,0) has gcd =4= 4, giving 4+1=54+1 = 5 lattice points. Segment (4,0)(4,0) to (0,3)(0,3) has gcd =1= 1, giving 22 lattice points (just the endpoints). Segment (0,3)(0,3) to (0,0)(0,0) has gcd =3= 3, giving 44 lattice points. Total boundary b=5+2+43=8b = 5 + 2 + 4 - 3 = 8.
  • Interior lattice points: triangle is small; checking shows i=3i = 3.
  • Pick's area =3+821=3+41=6= 3 + \frac{8}{2} - 1 = 3 + 4 - 1 = 6.
  • Formula area =12×4×3=6= \frac{1}{2} \times 4 \times 3 = 6. ✓

Try it yourself

  1. An L-shape is formed by a 7×37 \times 3 rectangle and a 4×24 \times 2 rectangle. Find its area (assume they fit cleanly).
  2. A rectangular room is 1212 m by 99 m. A square pillar of side 22 m takes some floor space. What is the floor area you can walk on?
  3. A path of 22 m wide runs along the inside of a 2020 m by 1515 m garden. Find the path area.
  4. A T-shape is formed by stacking a 6×26 \times 2 rectangle on top of a 4×24 \times 2 rectangle (centred). Find the total area.
  5. A leaf covers 2020 full grid squares and 1212 partial squares on 11-cm graph paper. Estimate its area.
  6. A picture frame has outer size 3030 cm by 2020 cm and inner picture 2424 cm by 1414 cm. Find the frame area.
  7. Pick's theorem: a triangle has vertices at (0,0)(0,0), (5,0)(5,0), (0,5)(0,5). Find its area (a) by formula and (b) using Pick's theorem.
  8. Find the area of a rectangle 4×64 \times 6 with a corner triangle of legs 22 and 33 cut out.

Activity

Map area estimate. Pick a small state of India on a map , say Goa or Kerala. Place a transparent grid over it (or trace the state onto graph paper). Count the unit squares to estimate the area in "map units". If the map's scale tells you how many real km each grid square stands for, convert your estimate to km². Compare with the official area.

Practice quiz

Quick check on this topic.

Quiz
Quick check : Irregular shapes
6 questions · pick the best answer
Q1

Area of an irregular shape is found by:

Q2

L-shape: two rectangles 4x3 and 2x5. Total area:

Q3

On grid paper, count squares to estimate:

Q4

Shape made of a 6x4 rectangle with a 2x2 square cut out has area:

Q5

Half-filled grid squares are typically counted as:

Q6

Splitting a trapezium into a rectangle and two triangles helps find its: