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Linking numbers and shapes

So far we have looked at number sequences and shape sequences separately. The real beauty appears when the two meet , when a shape sequence is literally counting out a number sequence, or when a number sequence becomes a hidden geometry. This is the deepest idea in Chapter 1.

Concept

Consider the triangular numbers again: 1,3,6,10,15,1, 3, 6, 10, 15, \dots. They are not just numbers; they are pictures. The nnth triangular number is the number of dots in a triangle of side nn. So triangular numbers and triangles of dots are the same thing in two languages , arithmetic and geometry.

The same is true for square numbers. The nnth square number n2n^2 is the count of dots in an n×nn \times n array. Whenever you see a 5×55 \times 5 chessboard square or a window pane with 3636 panes, you are looking at a square number.

Some surprising bridges:

Sum of two consecutive triangular numbers gives a square. Try it:

  • T1+T2=1+3=4=22T_1 + T_2 = 1 + 3 = 4 = 2^2.
  • T2+T3=3+6=9=32T_2 + T_3 = 3 + 6 = 9 = 3^2.
  • T3+T4=6+10=16=42T_3 + T_4 = 6 + 10 = 16 = 4^2.

Why? Place a triangle of side nn next to an upside-down triangle of side n+1n+1. They fit together exactly to form an (n+1)×(n+1)(n+1) \times (n+1) square. Number rule and picture proof , together.

Sum of first nn odd numbers equals n2n^2. We saw the gnomon proof in section 3.

Counting numbers and steps. A staircase with nn steps uses 1+2++n=Tn1 + 2 + \dots + n = T_n blocks. So if you ever build a staircase out of bricks, the brick count is a triangular number.

Powers of 2 and folding paper. Fold a strip of paper in half; you get 22 layers. Fold again; 44 layers. Again; 88 layers. The thickness sequence is exactly 2,4,8,16,32,2, 4, 8, 16, 32, \dots , the powers of 22, growing as you double.

Hexagonal numbers. Pebbles arranged in concentric hexagons give the sequence 1,7,19,37,1, 7, 19, 37, \dots. Each new ring adds 66 more than the last (+6,+12,+18,+6, +12, +18, \dots). Hexagonal numbers are cousins of triangulars and squares , geometry from a different shape gives a different number family.

The lesson: when a number puzzle feels hard, try drawing it. When a shape puzzle feels hard, try counting it. Mathematicians switch between the two languages constantly , it is like having two pairs of eyes.

Worked examples

Example 1. Use the rule Tn1+Tn=n2T_{n-1} + T_n = n^2 to find T9+T10T_9 + T_{10}.

  • It must equal 102=10010^2 = 100.
  • Check: T9=9×102=45T_9 = \frac{9 \times 10}{2} = 45 and T10=10×112=55T_{10} = \frac{10 \times 11}{2} = 55.
  • 45+55=10045 + 55 = 100.

Example 2. A pile of bricks is laid in a staircase with 1515 steps. How many bricks?

  • T15=15×162=120T_{15} = \frac{15 \times 16}{2} = 120.

Example 3. A square grid of dots has 144144 dots in total. How many dots on a side?

  • n2=144n=12n^2 = 144 \Rightarrow n = 12. So a 12×1212 \times 12 grid.

Example 4. Paper of thickness 0.10.1 mm is folded 77 times. How thick is the stack? (Assume folding is possible.)

  • After 77 folds, layers =27=128= 2^7 = 128.
  • Thickness =128×0.1= 128 \times 0.1 mm =12.8= 12.8 mm, just over a centimetre.

Try it yourself

  1. Verify that T5+T6=62T_5 + T_6 = 6^2.
  2. A staircase has 2020 steps. How many bricks does it use?
  3. A square has 625625 small tiles arranged in a square pattern. How many tiles on a side?
  4. Continue the hexagonal numbers 1,7,19,37,1, 7, 19, 37, \dots for two more terms.
  5. Fold a paper 1010 times in your head. How many layers?
  6. Find a pair of triangular numbers whose sum is 2525.
  7. Challenge: Are there triangular numbers that are also square? Find one besides 11.

Activity

Two languages, one picture. On grid paper, draw a 5×55 \times 5 square of dots. Now draw a slanted line from one corner that splits the square into two triangles of dots. Count the dots in each triangle. Do they add up to 2525? Are they triangular numbers? Write the two-sentence explanation of why they had to be triangular numbers.

Practice quiz

Quick check on this topic.

Quiz
Quick check : Linking numbers and shapes
6 questions · pick the best answer
Q1

The number 36 is both:

Q2

Sum of two consecutive triangular numbers gives:

Q3

Number of edges in a cube:

Q4

Number of faces in a cube:

Q5

Number of vertices in a cube:

Q6

1+3+5+...+(2n1)=1+3+5+...+(2n-1) =