Math Lab
Home/Class IX/Chapter 11

Chapter 11: Surface Areas and Volumes

The world is full of three-dimensional shapes: boxes, cans, cones, balls. This chapter equips you with formulas for the surface area and volume of the six most common shapes , the cuboid, cube, right circular cylinder, right circular cone, sphere, and hemisphere , and shows you how to apply them to real-life objects.

Each shape gets two formulas: one for surface area (the total area of its outer surface) and one for volume (the amount of space it occupies). Some shapes have additional formulas for the lateral or curved surface area, which is the surface excluding the bases. The chapter is light on theory and heavy on practical computation: identify the shape, plug into the formula, simplify, and compute.

Surface areas and volumes are everywhere: how much paint covers a wall, how much water a tank holds, how much wrapping paper covers a box, how much fuel a tank can store, how much carpet covers a floor. Every such question reduces to choosing the right shape, the right formula, and computing carefully.

A note on π\pi: many problems use π227\pi \approx \tfrac{22}{7} for convenience. Some use the more accurate value π3.14\pi \approx 3.14. Always read the question to see which value is requested, and use it consistently throughout the problem.

By the end of the chapter you should be able to compute the surface area and volume of any of the six shapes from given dimensions, identify which shape a real-world object resembles, and combine shapes (e.g. a hemisphere on top of a cylinder) to model composite objects.

What's inside

  • Cuboid and cube , the simplest 3D shapes, with rectangular faces.
  • Right circular cylinder , like a can; curved surface + two circular bases.
  • Right circular cone , like a party hat; curved surface + circular base.
  • Sphere , perfect 3D symmetry, like a ball.
  • Hemisphere , half a sphere; curved surface + flat circular base.

Key results / Formula card

ShapeSurface areaVolume
Cube (side aa)6a26a^2a3a^3
Cuboid (length \ell, breadth bb, height hh)2(b+bh+h)2(\ell b + bh + h\ell)bh\ell b h
Cylinder (radius rr, height hh)Curved: 2πrh2\pi r h; Total: 2πr(h+r)2\pi r(h+r)πr2h\pi r^2 h
Cone (radius rr, height hh, slant \ell)Curved: πr\pi r \ell; Total: πr(+r)\pi r (\ell+r)13πr2h\tfrac{1}{3}\pi r^2 h
Sphere (radius rr)4πr24\pi r^243πr3\tfrac{4}{3}\pi r^3
Hemisphere (radius rr)Curved: 2πr22\pi r^2; Total: 3πr23\pi r^223πr3\tfrac{2}{3}\pi r^3
Cone slant height=r2+h2\ell = \sqrt{r^2 + h^2}

Memorise this card. Almost every problem in the chapter is a direct application of one of these formulas.

Sub-topics

5 pages

Practice quiz

Answer the questions; explanations appear after each.

Quiz
Surface Areas and Volumes : Mixed practice
10 questions · pick the best answer
Q1

Curved surface area of a cylinder of radius rr and height hh is:

Q2

Total surface area of a cube of side 7 cm is:

Q3

Volume of a cube of side 5 cm is:

Q4

The slant height ll of a cone with radius rr and height hh is:

Q5

Surface area of a sphere of radius rr is:

Q6

Volume of a hemisphere of radius rr is:

Q7

A cuboid 10 cm ×\times 6 cm ×\times 4 cm has total surface area:

Q8

If a cone and a cylinder have the same base and height, ratio of cone's volume to cylinder's is:

Q9

Volume of a cylinder of radius 7 cm and height 10 cm (use π=22/7\pi=22/7) is:

Q10

A sphere of radius 3 cm is melted and recast into a sphere of radius 6 cm. The number of original spheres needed is: